8x^2+6x-27=0

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Solution for 8x^2+6x-27=0 equation:



8x^2+6x-27=0
a = 8; b = 6; c = -27;
Δ = b2-4ac
Δ = 62-4·8·(-27)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-30}{2*8}=\frac{-36}{16} =-2+1/4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+30}{2*8}=\frac{24}{16} =1+1/2 $

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